Bernoulli Distribution.Sample Method
Definition
Assembly: Extreme.Numerics (in Extreme.Numerics.dll) Version: 8.1.23
Overload List
Sample() | Returns a random sample from the distribution. |
Sample( | Returns a vector of random samples from the distribution. |
Sample( | Returns a random sample from the distribution. |
Sample( | Returns a vector of random samples from the distribution. |
Sample( | Returns a single random sample from a Bernoulli distribution with the specified success rate. |
Sample( | Fills an Int32 array with random numbers. |
Sample( | Fills an Int32 array with random numbers from this DiscreteDistribution. |
Sample(Random)
public override int Sample(
Random random
)
Parameters
- random Random
- The Random derived random number generator used to generate the sample.
Return Value
Int32A signed 32-bit integer.
Remarks
This method uses the random number generator specified by random to generate a random sample from the distribution. The return values of successive calls to this method follow the distribution represented by this BernoulliDistribution.
The Bernoulli distribution has two possible outcomes: 0 ('success') or 1 ('failure').
Exceptions
ArgumentNullException | random is null. |
Sample(Random, Double)
public static int Sample(
Random random,
double probability
)
Parameters
- random Random
- The Random derived random number generator used to generate the sample.
- probability Double
- The probability of a trial resulting in success.
Return Value
Int32A 32-bit signed integer sample from the Bernoulli distribution with the specified parameter.
Remarks
This method is useful when only a single random sample is required, or if the parameters of the distribution change often. To obtain a large number of samples from a distribution with identical parameters, create an instance of the class and call the Sample() method repeatedly.
Exceptions
ArgumentOutOfRangeException | probability is less than zero or greater than 1. |
ArgumentNullException | random is null. |