Bernoulli Distribution.Sample Method
Definition
Assembly: Numerics.NET (in Numerics.NET.dll) Version: 9.1.3
Overload List
Sample() | Returns a random sample from the distribution. |
Sample( | Returns a vector of random samples from the distribution. |
Sample( | Returns a random sample from the distribution. |
Sample( | Returns a vector of random samples from the distribution. |
Sample( | Returns a single random sample from a Bernoulli distribution with the specified success rate. |
Sample( | Fills an Int32 array with random numbers. |
Sample( | Fills an Int32 array with random numbers from this DiscreteDistribution. |
Sample(Random)
public override int Sample(
Random random
)
Parameters
- random Random
- A Random object that specifies the uniform random number generator that is to be used to generate the samples.
Return Value
Int32A signed 32-bit integer.
Remarks
This method uses the random number generator specified by random to generate a random sample from the distribution. The return values of successive calls to this method follow the statistical distribution represented by this distribution.
Sample(Random, Double)
public static int Sample(
Random random,
double probability
)
Parameters
- random Random
- The Random derived random number generator used to generate the sample.
- probability Double
- The probability of a trial resulting in success.
Return Value
Int32A 32-bit signed integer sample from the Bernoulli distribution with the specified parameter.
Remarks
This method is useful when only a single random sample is required, or if the parameters of the distribution change often. To obtain a large number of samples from a distribution with identical parameters, create an instance of the class and call the Sample() method repeatedly.
Exceptions
Argument | probability is less than zero or greater than 1. |
Argument | random is null. |