Interval.Subtract Method

Definition

Namespace: Numerics.NET
Assembly: Numerics.NET (in Numerics.NET.dll) Version: 9.0.3

Subtract(Double, Interval)	Returns an interval negated and shifted to the right by a specified value.
Subtract(Interval, Interval)	Returns the sum of two intervals.
Subtract(Interval, Double)	Returns an interval shifted to the left by a specified value.

Returns an interval negated and shifted to the right by a specified value.

public static Interval Subtract(
	double shift,
	Interval interval
)

Visual Basic

Public Shared Function Subtract ( 
	shift As Double,
	interval As Interval
) As Interval

C++/CLI

public:
static Interval Subtract(
	double shift, 
	Interval interval
)

static member Subtract : 
        shift : float * 
        interval : Interval -> Interval

Interval
The interval whose bounds are the difference between shift and the bounds of interval.

Returns the sum of two intervals.

public static Interval Subtract(
	Interval interval1,
	Interval interval2
)

Visual Basic

Public Shared Function Subtract ( 
	interval1 As Interval,
	interval2 As Interval
) As Interval

C++/CLI

public:
static Interval Subtract(
	Interval interval1, 
	Interval interval2
)

static member Subtract : 
        interval1 : Interval * 
        interval2 : Interval -> Interval

Interval
The interval whose bounds are the difference between the bounds of interval1 and interval2.

Returns an interval shifted to the left by a specified value.

public static Interval Subtract(
	Interval interval,
	double shift
)

Visual Basic

Public Shared Function Subtract ( 
	interval As Interval,
	shift As Double
) As Interval

C++/CLI

public:
static Interval Subtract(
	Interval interval, 
	double shift
)

static member Subtract : 
        interval : Interval * 
        shift : float -> Interval

Interval
The interval whose bounds are the difference between the bounds of interval and shift.